Integrand size = 25, antiderivative size = 107 \[ \int \frac {a+b \arccos (c x)}{x^2 \left (d-c^2 d x^2\right )} \, dx=-\frac {a+b \arccos (c x)}{d x}+\frac {2 c (a+b \arccos (c x)) \text {arctanh}\left (e^{i \arccos (c x)}\right )}{d}+\frac {b c \text {arctanh}\left (\sqrt {1-c^2 x^2}\right )}{d}-\frac {i b c \operatorname {PolyLog}\left (2,-e^{i \arccos (c x)}\right )}{d}+\frac {i b c \operatorname {PolyLog}\left (2,e^{i \arccos (c x)}\right )}{d} \]
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Time = 0.10 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {4790, 4750, 4268, 2317, 2438, 272, 65, 214} \[ \int \frac {a+b \arccos (c x)}{x^2 \left (d-c^2 d x^2\right )} \, dx=\frac {2 c \text {arctanh}\left (e^{i \arccos (c x)}\right ) (a+b \arccos (c x))}{d}-\frac {a+b \arccos (c x)}{d x}-\frac {i b c \operatorname {PolyLog}\left (2,-e^{i \arccos (c x)}\right )}{d}+\frac {i b c \operatorname {PolyLog}\left (2,e^{i \arccos (c x)}\right )}{d}+\frac {b c \text {arctanh}\left (\sqrt {1-c^2 x^2}\right )}{d} \]
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Rule 65
Rule 214
Rule 272
Rule 2317
Rule 2438
Rule 4268
Rule 4750
Rule 4790
Rubi steps \begin{align*} \text {integral}& = -\frac {a+b \arccos (c x)}{d x}+c^2 \int \frac {a+b \arccos (c x)}{d-c^2 d x^2} \, dx-\frac {(b c) \int \frac {1}{x \sqrt {1-c^2 x^2}} \, dx}{d} \\ & = -\frac {a+b \arccos (c x)}{d x}-\frac {c \text {Subst}(\int (a+b x) \csc (x) \, dx,x,\arccos (c x))}{d}-\frac {(b c) \text {Subst}\left (\int \frac {1}{x \sqrt {1-c^2 x}} \, dx,x,x^2\right )}{2 d} \\ & = -\frac {a+b \arccos (c x)}{d x}+\frac {2 c (a+b \arccos (c x)) \text {arctanh}\left (e^{i \arccos (c x)}\right )}{d}+\frac {b \text {Subst}\left (\int \frac {1}{\frac {1}{c^2}-\frac {x^2}{c^2}} \, dx,x,\sqrt {1-c^2 x^2}\right )}{c d}+\frac {(b c) \text {Subst}\left (\int \log \left (1-e^{i x}\right ) \, dx,x,\arccos (c x)\right )}{d}-\frac {(b c) \text {Subst}\left (\int \log \left (1+e^{i x}\right ) \, dx,x,\arccos (c x)\right )}{d} \\ & = -\frac {a+b \arccos (c x)}{d x}+\frac {2 c (a+b \arccos (c x)) \text {arctanh}\left (e^{i \arccos (c x)}\right )}{d}+\frac {b c \text {arctanh}\left (\sqrt {1-c^2 x^2}\right )}{d}-\frac {(i b c) \text {Subst}\left (\int \frac {\log (1-x)}{x} \, dx,x,e^{i \arccos (c x)}\right )}{d}+\frac {(i b c) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{i \arccos (c x)}\right )}{d} \\ & = -\frac {a+b \arccos (c x)}{d x}+\frac {2 c (a+b \arccos (c x)) \text {arctanh}\left (e^{i \arccos (c x)}\right )}{d}+\frac {b c \text {arctanh}\left (\sqrt {1-c^2 x^2}\right )}{d}-\frac {i b c \operatorname {PolyLog}\left (2,-e^{i \arccos (c x)}\right )}{d}+\frac {i b c \operatorname {PolyLog}\left (2,e^{i \arccos (c x)}\right )}{d} \\ \end{align*}
Time = 0.48 (sec) , antiderivative size = 158, normalized size of antiderivative = 1.48 \[ \int \frac {a+b \arccos (c x)}{x^2 \left (d-c^2 d x^2\right )} \, dx=-\frac {2 a+2 b \arccos (c x)+2 b c x \arccos (c x) \log \left (1-e^{i \arccos (c x)}\right )-2 b c x \arccos (c x) \log \left (1+e^{i \arccos (c x)}\right )+2 b c x \log (x)+a c x \log (1-c x)-a c x \log (1+c x)-2 b c x \log \left (1+\sqrt {1-c^2 x^2}\right )+2 i b c x \operatorname {PolyLog}\left (2,-e^{i \arccos (c x)}\right )-2 i b c x \operatorname {PolyLog}\left (2,e^{i \arccos (c x)}\right )}{2 d x} \]
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Time = 3.49 (sec) , antiderivative size = 146, normalized size of antiderivative = 1.36
method | result | size |
parts | \(-\frac {a \left (\frac {c \ln \left (c x -1\right )}{2}-\frac {c \ln \left (c x +1\right )}{2}+\frac {1}{x}\right )}{d}-\frac {b c \left (\frac {\arccos \left (c x \right )}{c x}+i \operatorname {dilog}\left (c x +i \sqrt {-c^{2} x^{2}+1}\right )+i \operatorname {dilog}\left (1+c x +i \sqrt {-c^{2} x^{2}+1}\right )+2 i \arctan \left (c x +i \sqrt {-c^{2} x^{2}+1}\right )-\arccos \left (c x \right ) \ln \left (1+c x +i \sqrt {-c^{2} x^{2}+1}\right )\right )}{d}\) | \(146\) |
derivativedivides | \(c \left (-\frac {a \left (\frac {1}{c x}+\frac {\ln \left (c x -1\right )}{2}-\frac {\ln \left (c x +1\right )}{2}\right )}{d}-\frac {b \left (\frac {\arccos \left (c x \right )}{c x}+i \operatorname {dilog}\left (c x +i \sqrt {-c^{2} x^{2}+1}\right )+i \operatorname {dilog}\left (1+c x +i \sqrt {-c^{2} x^{2}+1}\right )+2 i \arctan \left (c x +i \sqrt {-c^{2} x^{2}+1}\right )-\arccos \left (c x \right ) \ln \left (1+c x +i \sqrt {-c^{2} x^{2}+1}\right )\right )}{d}\right )\) | \(149\) |
default | \(c \left (-\frac {a \left (\frac {1}{c x}+\frac {\ln \left (c x -1\right )}{2}-\frac {\ln \left (c x +1\right )}{2}\right )}{d}-\frac {b \left (\frac {\arccos \left (c x \right )}{c x}+i \operatorname {dilog}\left (c x +i \sqrt {-c^{2} x^{2}+1}\right )+i \operatorname {dilog}\left (1+c x +i \sqrt {-c^{2} x^{2}+1}\right )+2 i \arctan \left (c x +i \sqrt {-c^{2} x^{2}+1}\right )-\arccos \left (c x \right ) \ln \left (1+c x +i \sqrt {-c^{2} x^{2}+1}\right )\right )}{d}\right )\) | \(149\) |
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\[ \int \frac {a+b \arccos (c x)}{x^2 \left (d-c^2 d x^2\right )} \, dx=\int { -\frac {b \arccos \left (c x\right ) + a}{{\left (c^{2} d x^{2} - d\right )} x^{2}} \,d x } \]
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\[ \int \frac {a+b \arccos (c x)}{x^2 \left (d-c^2 d x^2\right )} \, dx=- \frac {\int \frac {a}{c^{2} x^{4} - x^{2}}\, dx + \int \frac {b \operatorname {acos}{\left (c x \right )}}{c^{2} x^{4} - x^{2}}\, dx}{d} \]
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\[ \int \frac {a+b \arccos (c x)}{x^2 \left (d-c^2 d x^2\right )} \, dx=\int { -\frac {b \arccos \left (c x\right ) + a}{{\left (c^{2} d x^{2} - d\right )} x^{2}} \,d x } \]
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\[ \int \frac {a+b \arccos (c x)}{x^2 \left (d-c^2 d x^2\right )} \, dx=\int { -\frac {b \arccos \left (c x\right ) + a}{{\left (c^{2} d x^{2} - d\right )} x^{2}} \,d x } \]
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Timed out. \[ \int \frac {a+b \arccos (c x)}{x^2 \left (d-c^2 d x^2\right )} \, dx=\int \frac {a+b\,\mathrm {acos}\left (c\,x\right )}{x^2\,\left (d-c^2\,d\,x^2\right )} \,d x \]
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